回复：【Gary_zhang5】基于51单片机的摇摇棒制作（并非设计）

下面为大家详细介绍一下。
中间的那部分便是51最小系统，下面的ISP是一个下载端口，买现成的51板的话可以忽略这部分。
右边便是最主要的制作部分。首先用万用表逐个测量二极管是否能正常工作，可以使用万用表的通断路档，分别将万用表的黑线和红线接在LED的两个引脚上，注意正负极，如果LED能正常发光，说明二极管没有问题。十六个LED整齐地排成一排，尽量保持间距相等。将所有LED的正极接在一起，这里要说明的是，LED有两个引脚，长正短负，也就是说把所有的长脚接在一起，通过4007二极管连接在电路的正极。一定要注意二极管和LED的电流方向，4007二极管有银色圈的那一端是负极。

将LED焊接在洞洞板之后，可以用剪刀剪去多余的引脚，看起来更加美观。
接IN4007的正极和51板的正极是连在一起的，这里电源用3接5号电池就可以。
在P3_0出接一个按键开关，用来切换画面。我们采用的开关有四个脚，其中两两相通，我们先用万用表的通路档检查可作为开关的那一组脚，然后再进行焊接。这里最好像电路图中那样加上一个10K的电阻。
现在只剩下LED的负极了，按照先后顺序，从第一个灯开始，依次和单片机的P0_0一直到P2_7链接起来，这里要注意链接顺序。
因为单片机上是按照P0_0到P0_7，P2_7到P2_0的顺序来排列的，而我们焊接的时候要按照P0_0到P0_7，P2_0到P2_7的顺序来焊接，因为这样的顺序方便编写程序。

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unsigned char code tuan_3[]={
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0x7f,0xfe,0x7f,0xfe,0x00,0x00,
0x00,0x00,0x7f,0xfe,0x7f,0xfe,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xf1,0xff,0xe0,0xff,
0xc0,0x7f,0x80,0x3f,0x00,0x1f,0x00,0x0f,
0x00,0x07,0x80,0x03,0xc0,0x01,0xf0,0x00,
0xc0,0x01,0x80,0x03,0x00,0x07,0x00,0x0f,
0x00,0x1f,0x80,0x3f,0xc0,0x7f,0xe0,0xff,
0xf1,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0x00,0x03,0x00,0x01,
0x00,0x01,0xff,0xf8,0xff,0xf8,0xff,0xf8,
0xff,0xf8,0xff,0xf8,0xff,0xf8,0xff,0xf8,
0xff,0xf8,0x00,0x00,0x00,0x01,0x00,0x03,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff};//I? U
unsigned char code tuan_0[]={
0xff,0xff,0xff,0xff,0xe0,0x0f,0xed,0xdf,
0xed,0xdf,0xed,0xdf,0xed,0xdf,0x00,0x03,
0xed,0xdd,0xed,0xdd,0xed,0xdd,0xed,0xdd,
0xe0,0x0d,0xff,0xfd,0xff,0xf1,0xff,0xff,
0xff,0x7f,0xff,0x7f,0xbf,0x7f,0xbf,0x7f,
0xbf,0x7f,0xbf,0x7d,0xbf,0x7e,0xb8,0x01,
0xb7,0x7f,0xaf,0x7f,0x9f,0x7f,0xbf,0x7f,
0xff,0x7f,0xfe,0x7f,0xff,0x7f,0xff,0xff,
0xef,0x7f,0xef,0x7d,0xee,0xfe,0x00,0x01,
0xed,0xff,0xeb,0xfd,0xff,0xfd,0xec,0xfb,
0xed,0x37,0xed,0xcf,0x01,0xcf,0xed,0xb7,
0xec,0x7b,0xed,0xf9,0xef,0xfb,0xff,0xff,
0xf7,0xf7,0xf7,0xf7,0xf7,0xef,0xf7,0xdf,
0xf7,0xbf,0xf6,0x7f,0xf5,0xff,0x00,0x01,
0xf5,0xff,0xf6,0xff,0xb7,0x7f,0xd7,0x9f,
0xf7,0xcf,0xf7,0xe7,0xf7,0xef,0xff,0xff};//电子技术
unsigned char code tuan_4[]={
0xff,0xff,0xfe,0xff,0xfe,0xff,0xfe,0xff,
0xfe,0xff,0xfe,0xff,0xfe,0xff,0xfe,0xff,
0xfe,0xff,0xfe,0xff,0xfe,0xff,0xfe,0xff,
0xfe,0xff,0xfc,0xff,0xfe,0xff,0xff,0xff,
0xff,0x7f,0xfe,0xfd,0xf9,0xfd,0x87,0x7d,
0xf7,0x7d,0xf7,0x7d,0xf7,0x7d,0xf7,0x7d,
0x00,0x01,0xb7,0x7d,0xf7,0x7d,0xf7,0x7d,
0xe6,0x7d,0xf7,0x79,0xff,0xfd,0xff,0xff,
0xff,0xbf,0xdf,0x7f,0xde,0xff,0xdd,0xff,
0xd8,0x00,0xd3,0x6f,0xcb,0x6f,0x1b,0x6f,
0xdb,0x6b,0xdb,0x6d,0xdb,0x6c,0xd8,0x01,
0xdf,0xff,0xdf,0xff,0xdf,0xff,0xff,0xff,
0xfe,0xff,0xfd,0xff,0xf0,0x01,0xcb,0xff,
0x3d,0xf7,0xfb,0xcf,0xe6,0x3f,0x0f,0x7b,
0xaf,0xfd,0xe8,0x03,0xef,0xff,0xee,0xff,
0xeb,0x3f,0xc7,0xc7,0xef,0xef,0xff,0xff};//一生有你
unsigned char code tuan_5[]={
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xf8,0x1f,0xe7,0xe7,0xdf,0xfb,
0xbf,0xfd,0x7f,0xfe,0x7f,0xfe,0xff,0xff,
0xff,0xef,0xc1,0xdf,0xbf,0xaf,0x7f,0xe7,
0xbf,0xf3,0xc1,0xf1,0xff,0xf1,0xff,0xf1,
0xff,0xf1,0xff,0xf1,0xff,0xf1,0xc1,0xf1,
0xbf,0xf3,0x7f,0xe7,0xbf,0xaf,0xc1,0xdf,
0xff,0xef,0xff,0xff,0x7f,0xfe,0x7f,0xfe,
0xbf,0xfd,0xdf,0xfb,0xe7,0xe7,0xf8,0x1f,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff};//（^-^）

void LED() //LED显示
{
for(i=0,j=1;i<=127,j<=128;i=i+2,j=j+2)
{
if(k==0)
{
P1=tuan_0[i],P3=tuan_0[j];
delay(1);
}
elseif(k==1)
{
P1=tuan_1[i],P3=tuan_1[j];
delay(1);
}
elseif(k==2)
{
P1=tuan_2[i],P3=tuan_2[j];
delay(1);
}
elseif(k==3)
{
P1=tuan_3[i],P3=tuan_3[j];
delay(1);
}
elseif(k==4)
{
P1=tuan_4[i],P3=tuan_4[j];
delay(1);
}
elseif(k==5)
{
P1=tuan_5[i],P3=tuan_5[j];
delay(1);
}
}
}
void main(void) //主函数
{
while(1)
{
key();
LED();
}
}