新手问个问题，a.php怎么向b.php传值，不通过表单提交的方式

我已经对我主管绝望了

<?php
$filename="game1".microtime_float().".wav";//要生成的图片名字
$filejing="Wav/game1/".$filename;
$xmlstr = $GLOBALS[HTTP_RAW_POST_DATA];
if(empty($xmlstr)) {
$xmlstr = file_get_contents('php://input');
}
$wavs = $xmlstr;//得到post过来的二进制原始数据
$file = fopen("D:/xampp/htdocs/Pinggu/Wav/game1/".$filename,"w");//打开文件准备写入
fwrite($file,$wavs);//写入
fclose($file);//关闭
$dataList = $filename;
header("http://localhost/Pinggu/php/game1.php?data=".$dataList );
function microtime_float()
{
list($usec, $sec) = explode(" ", microtime());
return ((float)$usec + (float)$sec);
}
?>
这是b.php

<?php
echo "ss=123&message=$yonghuID";
$dataList = unserialize( $_GET['data'] );
$yonghuID = $_POST["value1"]; //获取flash传递过来的参数
$NumberID = $_POST["value2"];
$con = mysql_connect("localhost","root","");
mysql_select_db("pinggu",$con);
mysql_query("set names 'utf8'");
mysql_query("set @xyonghuID='$yonghuID'");
mysql_query("set @xNumberID='$NumberID'");
mysql_query("set @xfilename='$dataList'");
mysql_query("set @xfile='$filejing'");
$result=mysql_query("call _game1(@xyonghuID,@xNumberID,@xfilename,@xfile)");
mysql_close($con);
?>
这是A.php