【指导】如何用138译码器同时点亮八个数码管啊？大神指导下，谢

138是不可能同时点亮的。你只能增快扫描的速度。达到近似同时的效果。

#include <reg52.h>
sbit LA=P2^2;
sbit LB=P2^3;
sbit LC=P2^4;
void main()
{
while(1)
{
LA=0;LB=0;LC=0;P0=0x06;
LA=0;LB=0;LC=1;P0=0x5b;
LA=0;LB=1;LC=0;P0=0x4f;
LA=0;LB=1;LC=1;P0=0x66;
LA=1;LB=0;LC=0;P0=0x6d;
LA=1;LB=0;LC=1;P0=0x7d;
LA=1;LB=1;LC=0;P0=0x07;
LA=1;LB=1;LC=1;P0=0x7f;
}
}

#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int
#define Dis P0
sbit LSA=P2^2;
sbit LSB=P2^3;
sbit LSC=P2^4;
#define dis P0;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
void delay(uint);
void main()
{
uint j;
uchar i;
while(1)
{
for(i=0;i<8;i++)
{
switch(i)
{
case(0):
LSA=0;LSB=0;LSC=0; break;
case(1):
LSA=1;LSB=0;LSC=0; break;
case(2):
LSA=0;LSB=1;LSC=0; break;
case(3):
LSA=1;LSB=1;LSC=0; break;
case(4):
LSA=0;LSB=0;LSC=1; break;
case(5):
LSA=1;LSB=0;LSC=1; break;
case(6):
LSA=0;LSB=1;LSC=1; break;
case(7):
LSA=1;LSB=1;LSC=1; break;
}
Dis=table[i];
j=10;
while(j--);
Dis=0x00;
}
}
}

不清楚