菜鸟求助。。

还搞单片机啊，不是毕业了么

上百度一抓一大把。注意连线就得了

连电路都不贴出来，就叫大家帮你写程序。。

#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
uchar code table[]={0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f} ;
sbit a1=P2^2;
sbit a2=P2^3;
sbit a3=P2^4;
void daley(int z);
void main()
{
uint n,i;
for(n=0;n<8;n++)
{
switch(n)
{
case 0: a1=0;a2=0;a3=0;break;
case 1: a1=1;a2=0;a3=0;break;
case 2: a1=0;a2=1;a3=0;break;
case 3: a1=1;a2=1;a3=0;break;
case 4: a1=0;a2=0;a3=1;break;
case 5: a1=1;a2=0;a3=1;break;
case 6: a1=0;a2=1;a3=1;break;
case 7: a1=1;a2=1;a3=1;break;
default: break;
}
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
daley(100);
}
}
void daley(int z)
{
uint a,b;
for(;z>0;z--)
for(a=38;a>0;a--)
for(b=38;b>0;b--);
}

楼上这个可以吗？

#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
uchar code table[]={0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f} ;
sbit a1=P2^2;
sbit a2=P2^3;
sbit a3=P2^4;
void daley(int z);
void main()
{
while(1)
{
uint i;
a1=0;a2=0;a3=0;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=1;a2=0;a3=0;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=0;a2=1;a3=0;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=1;a2=1;a3=0;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=0;a2=0;a3=1;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=1;a2=0;a3=1;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=0;a2=1;a3=1;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
a1=1;a2=1;a3=1;
for(i=0;i<10;i++)
{
P0=table[i];
daley(50);
}
}
}
void daley(int z)
{
uint a,b;
for(;z>0;z--)
for(a=38;a>0;a--)
for(b=38;b>0;b--);
}那你试下这个，虽然我觉得换汤不换药

那可

#include<reg51.h>
#define uint unsigned int
#define uchar unsigned char
sbit a1=P2^2;
sbit a2=P2^3;
sbit a3=P2^4;
void delay(uint z)
{
uchar a,b;
for(a=z;a>0;a--)
for(b=110;b>0;b--);
}
uchar code table[]={0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,0x7f,0x6f};
void main()
{
while(1)
{
uint j,i;
for(i=0;i<10;i++)
{
for(j=0;j<8;j++)
{
switch(j)
{
case 0: a1=0;a2=0;a3=0;break;
case 1: a1=1;a2=0;a3=0;break;
case 2: a1=0;a2=1;a3=0;break;
case 3: a1=1;a2=1;a3=0;break;
case 4: a1=0;a2=0;a3=1;break;
case 5: a1=1;a2=0;a3=1;break;
case 6: a1=0;a2=1;a3=1;break;
case 7: a1=1;a2=1;a3=1;break;
}
P0=table[i];
delay(50);
P0=0x00;
}
delay(100);
}
}
}
这个·····在我的数码管上闪得太厉害了~你试下看看，如果你调好了，把程序给我看看

我没招了~

#include<reg51.h>
#define GPIO_DIG P0
sbit LSA=P2^2;
sbit LSB=P2^3;
sbit LSC=P2^4;
unsigned char code DIG_CODE[10]={
0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
unsigned char DisplayData[1];
void DigDisplay();
unsigned int Time1,K;
void TimerConfiguration()
{
TMOD=0X02;
TH0=0X9C;
TL0=0X9C;
ET0=1;
EA=1;
TR0=1;
}
void main(void)
{
unsigned char i;
for(i=0;i<10;i++)
{
DisplayData[i]=DIG_CODE[i];
}
TimerConfiguration();
while(1)
{
DigDisplay();
}
}
void DigDisplay()
{
unsigned char i;
unsigned int j;
for(i=0;i<8;i++)
{
switch(i)
{
case(0):
LSA=0;LSB=0;LSC=0; break;
case(1):
LSA=1;LSB=0;LSC=0; break;
case(2):
LSA=0;LSB=1;LSC=0; break;
case(3):
LSA=1;LSB=1;LSC=0; break;
case(4):
LSA=0;LSB=0;LSC=1; break;
case(5):
LSA=1;LSB=0;LSC=1; break;
case(6):
LSA=0;LSB=1;LSC=1; break;
case(7):
LSA=1;LSB=1;LSC=1; break;
}
GPIO_DIG=DIG_CODE[K];
j=10;
while(j--);
GPIO_DIG=0x00;
}
}
void Timer() interrupt 1
{
Time1++;
if(Time1>5000){
Time1=0;
++K;
if(K>9) K=0;
}
}