自挽…

1.声明字符串“000000”，先对000000的6位进行循环，
2.再对0-9的10位进行循环，替换字符串中的某个字符，打印出来，
3.声明数组a-z（排除r、o）再对a-z的24位进行循环，替换字符串的字符，打印出来
String str = "000000";
String[] t = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","p","q","s","t","u","v","w","x","y","z"};
String s = "";
for(int j=0; j<str.length(); j++)
{
for(int k=1; k<10; k++)
{
if(j == 0)
{
s = str.substring(0, str.length()-j-1) + k;
}
else
{
s = str.substring(0, str.length()-j-1) + k + str.substring(str.length()-j, str.length());
}
System.out.print(s + " ");
}
for(int m=0; m<t.length; m++)
{
if(j == 0)
{
s = str.substring(0, str.length()-j-1) + t[m];
}
else
{
s = str.substring(0, str.length()-j-1) + t[m] + str.substring(str.length()-j, str.length());
}
System.out.print(s + " ");
}
System.out.println();
}

自己想了一天，也写了一个，基本上实现了，在公司，先上个拍的照片

自挽

就此沉了么…

自挽…

挽…