二维list增加列的问题

l = [(1,11),(2,22),(3,33)]
z=['a','b','c']
k = [list(l[i])+[z[i]] for i in range(len(l))]
print(k)
#这个表达式获取的是返回值，append()返回的就是None

可以解决，怎么联系？

总结了几种方法，供大家参考一下:
l = [(1,11),(2,22),(3,33)]
z=['a','b','c']
# 01
k = [list(l[i])+[z[i]] for i in range(len(l))]
#02
newList = [list(x)+[y] for x,y in zip(l, z)]
#03
list_zip = list(zip(l,z))
newResult =[]
for x in list_zip:
newResult.append([element for tupl in x for element in tupl])
#04
list_k = [[l1,l2,z1] for (l1,l2),z1 in zip(l,z)]print(k)

本人问题中如果用append方法得这么写:
outerList, tempList = [], []
for x,y in zip(l, z):
tempList = list(x)
tempList.append(y)
outerList.append(tempList)
print(">>>>>>>>", outerList)
1楼我得问题在于tempList.append(y) 是改变tempList本身得si'ze, 整个语句不能赋值给一个变量。
再次感谢3楼朋友得热心提示!