"player_code": "A1", "player_raid_level": "A11", "previous_currency": "A12", "previous_rank": "A13", "raid_background_id": "A14", "raid_tickets_collected": "A15", "raid_wildcard_count": "A16", "raid_xp": "A17", "role": "A18", "score": A19,
一行文字，文本大小240k。其中具有多段同样格式的内容，A1、A11、A12.....A19变化，其余文字固定不变。
player_code.*?score.*?,
使用此代码找到如上文字，但中间一长串都不需要，最终只要 player_code": "A1", score": A19,
请教各位，如何实现提取文字的同时删除不需要的部分

"player_code": "A1", "player_raid_level": "A11", "previous_currency": "A12", "previous_rank": "A13", "raid_background_id": "A14", "raid_tickets_collected": "A15", "raid_wildcard_count": "A16", "raid_xp": "A17", "role": "A18", "score": A19,

"player_code": "A1", "player_raid_level": "A11", "previous_currency": "A12", "previous_rank": "A13", "raid_background_id": "A14", "raid_tickets_collected": "A15", "raid_wildcard_count": "A16", "raid_xp": "A17", "role": "A18", "score": A19,
一行文字，文本大小240k。其中具有多段同样格式的内容，A1、A11、A12.....A19变化，其余文字固定不变。
player_code.*?score.*?,
使用此代码找到如上文字，但中间一长串都不需要，最终只要 player_code": "A1", score": A19,

不知道包含什么和谐字眼......只能发图片了

最终只要 player_code":"A1",score":A19, 可以直接使用OR操作。

要删除其余的，可以使用“反向选择"。