n充分大时,1/16<1/xn<1/3
|x(n+3)-x(n+2)|=|(1/(x(n+2)^2)-1/(xn^2))|
=|(1/(x(n+2))+1/(xn))((x(n+2)-xn)/
(x(n+2)xn))|<|2(x(n+2)-xn)/27|
≤|2(x(n+2)-x(n+1))/27|+|2(x(n+1)-xn)/27|,随便选两个k一个奇数一个偶数满足
|x(k+2)-x(k+1)|<|x(k+1)-xk|
|x(k+3)-x(k+2)|<4|(x(k+1)-xk|/27
鉴定为柯西序列